MCAT content library / Chemistry & physics / Mass spectrometry and isotope patterns
Read a mass spectrum as mass-to-charge evidence, then use isotope clusters and fragments without assuming every peak equals a neutral molecular mass.
About 16 minutes, including charge-state and isotope-pattern examples.
Useful foundations
On this page
- The horizontal axis is mass-to-charge
- Concept: charge state can change where the same ion appears
- Worked application: read an isotope cluster
- Pattern: fragments are structural clues, not separate original molecules
- Rule: the most intense peak is not automatically the molecular ion
- Check your reasoning
- Continue learning
- Sources
The horizontal axis is mass-to-charge
Mass spectrometry detects ions. The horizontal coordinate is m/z: the ion’s mass divided by the magnitude of its charge in elementary-charge units. A singly charged ion with nominal mass 100 appears near m/z 100. If the same species carries a +2 charge, it can appear near m/z 50.
This distinction matters whenever a spectrum contains multiple charge states. A low m/z peak does not automatically mean a low molecular mass.
Concept: charge state can change where the same ion appears
For a simplified ion of mass M and charge z,
m/z ≈ M/z.
If an ion is observed at m/z 60 with z = +2, the corresponding ionic mass is about 120 mass units under the simplified model. Charge information must therefore be interpreted before assigning molecular mass.
Ionization methods differ in how much fragmentation and how many charge states they produce. A passage should identify the relevant ionization behavior if it matters to the inference.
Worked application: read an isotope cluster
An original spectrum shows a singly charged molecular-ion region with peaks at m/z 120 and 122 in an intensity ratio of approximately 3:1. The passage supplies that chlorine’s common isotopes produce an approximate 3:1 M:M+2 pattern when one chlorine atom is present, while one bromine atom produces a pattern closer to 1:1.
The 3:1 pair therefore supports a candidate containing one chlorine atom more strongly than a candidate containing one bromine atom under the supplied model.
| Candidate | Expected M:M+2 pattern supplied | Compatibility with 3:1 data |
|---|---|---|
| One Cl | ≈3:1 | Supported |
| One Br | ≈1:1 | Not supported |
| No heavy-isotope contributor in model | No strong M+2 pair | Not supported |
The spectrum does not prove the entire structure. It constrains elemental composition. NMR, IR, or fragmentation evidence may still be needed to distinguish constitutional isomers with the same molecular formula.
Pattern: fragments are structural clues, not separate original molecules
During ionization or subsequent gas-phase processes, a molecular ion can fragment. A fragment peak therefore can report a stable charged piece formed from the original molecule. Its m/z can help identify which bond cleavage is compatible with a candidate structure.
For example, if a proposed structure can produce a supplied stable fragment at m/z 43 but another candidate cannot generate that fragment without an implausible rearrangement under the passage’s stated rules, the fragment supports the first candidate.
Do not assume every peak represents a neutral compound that existed in the sample before ionization.
Rule: the most intense peak is not automatically the molecular ion
The tallest peak in a mass spectrum is called the base peak. It is assigned 100% relative intensity, but it may be a fragment rather than the molecular ion. Molecular-ion assignment depends on ionization method, exact mass region, isotope pattern, and other evidence.
Similarly, the highest m/z peak is not automatically the molecular ion if adducts, isotope peaks, or multiple charge states are present. Use the labels and experimental context provided.
ACTIVE PRACTICE · CHEMICAL EVIDENCE
Use Isotopes to Constrain the Formula
The lesson’s hypothetical singly charged molecular-ion region contains two peaks at m/z 120 and 122. Compare their supplied relative heights. The original passage states that one chlorine gives an approximate 3:1 M:M+2 pattern, whereas one bromine gives approximately 1:1.
One-Cl model: M = 100, M+2 ≈ 33 relative units.
These stipulated single-halogen patterns ignore other isotope contributions. Isotope spacing and isotope ratios constrain composition; they do not establish full connectivity.
Check your reasoning
Choose an answer before opening its feedback.
Check 1
An ion with charge +2 appears at m/z 75. What is its approximate ionic mass in the simplified model?
A. 150
Correct. M ≈ (m/z)z = 75 × 2.
B. 37.5
Review this choice. Charge divides mass to give m/z; recover mass by multiplying.
C. 75
Review this choice. That would correspond to z = 1.
D. 225
Review this choice. The stated charge is +2, not +3.
Check 2
A spectrum shows an M and M+2 pair in an approximately 1:1 ratio. The passage states this is characteristic of one bromine atom. Which inference is best supported?
A. A one-bromine candidate is supported by the isotope pattern.
Correct. The measured cluster matches the supplied bromine signature.
B. The complete molecular structure is uniquely proven.
Review this choice. Isotope evidence constrains composition but may not distinguish every isomer.
C. The ion must carry charge +2.
Review this choice. The M+2 spacing here refers to isotope mass difference, not charge state.
D. Bromine has only one isotope.
Review this choice. The pattern arises from multiple isotopes.
Check 3
The tallest peak in a spectrum occurs at m/z 43. Which statement is always true?
A. It is the base peak.
Correct. The tallest peak defines the base peak.
B. It must be the molecular ion.
Review this choice. The base peak can be a fragment.
C. The neutral molecule must have mass 43.
Review this choice. Fragmentation and charge state can make that inference invalid.
D. No heavier ion can be present.
Review this choice. Lower-intensity peaks can occur at larger m/z values.
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