MCAT content library / Biology & biochemistry / Kidney filtration and solute handling
Turn nephron transport into a mass-balance problem: what was filtered, what was reabsorbed, what was secreted, and what finally appeared in urine?
About 18 minutes, including filtered-load, excretion, and transport-saturation examples.
Useful foundations
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Start with the renal mass balance
The nephron handles a solute through four bookkeeping terms: filtration, reabsorption, secretion, and excretion. The relationship is:
Excretion = Filtration − Reabsorption + Secretion.
That equation is more reliable than memorizing whether every solute “goes up” or “goes down” in urine. If a solute is filtered and then almost completely reabsorbed, urinary excretion can be tiny even though filtration was large. If a solute is filtered and additionally secreted into the tubule, excretion can exceed the filtered amount.
Concept: filtration is not the same as excretion
Glomerular filtration transfers water and small dissolved substances from glomerular capillary plasma into Bowman’s space, subject to the filtration barrier. Cells and most large plasma proteins are retained under normal conditions. The filtered load of a freely filtered solute can be calculated as:
Filtered load = GFR × plasma concentration.
After filtration, tubular epithelial cells selectively reabsorb substances back to blood or secrete substances from blood into tubular fluid. What reaches the ureter is the result of all of those steps, not filtration alone.2
Worked application: calculate filtered and excreted loads
An original kidney model has a glomerular filtration rate of 120 mL/min. Plasma concentration of solute X is 2 mg/mL. Urine flow is 1.5 mL/min and urine concentration of X is 40 mg/mL. Assume X is freely filtered.
The filtered load is:
120 mL/min × 2 mg/mL = 240 mg/min.
The urinary excretion rate is:
1.5 mL/min × 40 mg/mL = 60 mg/min.
Therefore the kidney excretes 60 mg/min even though 240 mg/min was filtered. The difference—180 mg/min—represents net reabsorption if no additional information indicates simultaneous secretion.
| Quantity | Calculation | Result |
|---|---|---|
| Filtered load | 120 mL/min × 2 mg/mL | 240 mg/min |
| Excretion rate | 1.5 mL/min × 40 mg/mL | 60 mg/min |
| Net tubular handling | 240 − 60 | 180 mg/min net reabsorption |
If instead excretion had been 300 mg/min while filtered load remained 240 mg/min, the extra 60 mg/min would require net secretion into the tubule.
Pattern: transporters can saturate
Carrier-mediated tubular transport has finite capacity. For a reabsorbed solute such as glucose in a simplified model, filtered load rises linearly as plasma concentration rises. Reabsorption can rise with filtered load only until the relevant transporters approach their maximum transport rate. Beyond that point, additional filtered solute remains in tubular fluid and appears in urine.3
| Plasma X | Filtered X | Reabsorbed X | Excreted X |
|---|---|---|---|
| Low | 80 mg/min | 80 mg/min | 0 |
| Intermediate | 180 mg/min | 180 mg/min | 0 |
| High | 300 mg/min | 220 mg/min | 80 mg/min |
| Higher | 420 mg/min | 220 mg/min | 200 mg/min |
Once reabsorption plateaus at 220 mg/min, every additional milligram filtered appears in urine under this simplified model. The urinary threshold therefore reflects transporter capacity, not a sudden change in glomerular filtration physics.
Rule: clearance compares excretion with plasma concentration
Renal clearance is the virtual plasma volume from which a solute is completely removed per unit time:
Clearance = (urine concentration × urine flow) / plasma concentration.
For a freely filtered solute, clearance below GFR supports net reabsorption; clearance above GFR supports net secretion. A clearance close to GFR is consistent with little net tubular handling under the stated conditions. These interpretations depend on the assumptions that the solute is freely filtered and measured accurately.
Acid–base handling and nitrogen excretion use the same accounting mindset. Renal secretion of H⁺ and handling of bicarbonate affect systemic acid–base balance, while nitrogenous wastes such as urea are excreted after metabolism. Do not confuse “present in urine” with “made by the kidney.”
ACTIVE PRACTICE · RENAL PHYSIOLOGY
Account for What Enters and Leaves the Nephron
Start with the worked example: GFR 120 mL/min; plasma solute X 2 mg/mL; urine flow 1.5 mL/min; urinary solute X 40 mg/mL. Assume the solute is freely filtered.
Filtered load: mg/min. Excretion: mg/min. Net handling: . Clearance: mL/min.
Net transport does not reveal gross reabsorption and secretion separately. The model is a mass balance, not a particular named transporter.
Check your reasoning
Choose an answer before opening its feedback.
Check 1
A freely filtered solute has a filtered load of 100 mg/min and an excretion rate of 25 mg/min. Which conclusion is best supported?
A. There is net reabsorption of 75 mg/min.
Correct. Excretion is lower than filtration by 75 mg/min.
B. There is net secretion of 75 mg/min.
Review this choice. Net secretion would make excretion exceed filtration.
C. The solute was not filtered.
Review this choice. The filtered load is explicitly given as 100 mg/min.
D. Urine flow must be zero.
Review this choice. A nonzero excretion rate requires urine output.
Check 2
A reabsorptive transporter reaches its maximum rate while filtered load continues to rise. What happens to urinary excretion of the solute?
A. It begins to increase.
Correct. Filtered solute beyond the reabsorptive capacity remains in the tubular fluid.
B. It must fall to zero.
Review this choice. Saturation prevents complete reabsorption at high filtered loads.
C. GFR must become zero.
Review this choice. Transport saturation does not require filtration to stop.
D. The solute becomes a plasma protein.
Review this choice. Transport saturation does not change the solute’s chemical identity.
Check 3
A freely filtered solute has a clearance substantially greater than GFR. Which process is most consistent?
A. Net tubular secretion
Correct. More solute leaves in urine than filtration alone would account for.
B. Complete reabsorption
Review this choice. Complete reabsorption would drive clearance toward zero.
C. No filtration and no secretion
Review this choice. That would not produce clearance above GFR.
D. Increased hemoglobin binding
Review this choice. The relevant process is renal tubular handling.
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