MCAT content library / Chemistry & physics / Interference and diffraction
Read fringe spacing and diffraction envelopes as evidence about wavelength, aperture geometry, and path difference rather than as geometrical-ray images.
About 17 minutes, including the double-slit dataset and checks.
Useful foundations
On this page
- Interference comes from phase and path difference
- Concept: double-slit spacing tracks wavelength and slit separation
- Worked application: identify the changed parameter
- Pattern: diffraction creates an envelope
- Rule: X-ray diffraction can report structural spacing
- Check your reasoning
- Continue learning
- Sources
Interference comes from phase and path difference
When waves overlap, their displacements add. Waves arriving in phase reinforce one another, producing constructive interference. Waves arriving sufficiently out of phase can partially or completely cancel, producing destructive interference.
Interference patterns therefore encode differences in path length and phase. Bright and dark regions on a screen are not separate light rays tracing independent geometrical images; they are the spatial result of superposition.
Concept: double-slit spacing tracks wavelength and slit separation
For a double-slit experiment in the small-angle regime, adjacent bright-fringe spacing is approximately:
Δy = λL/d
where λ is wavelength, L is slit-to-screen distance, and d is slit separation. Fringe spacing therefore increases with wavelength and screen distance and decreases as slit separation increases.
This relation is useful because the same observed change can have several possible causes. A wider fringe pattern could mean a longer wavelength, a farther screen, or a smaller slit separation unless the experiment controls the other variables.
Worked application: identify the changed parameter
An original double-slit experiment uses monochromatic light with λ = 600 nm, a screen 2.0 m from the slits, and slit separation d = 0.50 mm.
The predicted fringe spacing is:
Δy = (600 × 10⁻⁹ m)(2.0 m)/(5.0 × 10⁻⁴ m) = 2.4 × 10⁻³ m = 2.4 mm.
Researchers then change one parameter at a time:
| Condition | Changed parameter | Expected fringe spacing |
|---|---|---|
| Control | — | 2.4 mm |
| A | λ doubled | 4.8 mm |
| B | d doubled | 1.2 mm |
| C | L halved | 1.2 mm |
Conditions B and C produce the same fringe spacing even though different physical parameters changed. A measured pattern alone can therefore be ambiguous unless the experimental geometry is known.
Pattern: diffraction creates an envelope
A finite slit also diffracts the wave passing through it. For a single slit of width a, minima occur approximately when
a sin θ = mλ, for nonzero integer m.
Narrower slits produce broader diffraction. In a real double-slit pattern, the fine interference fringes are often modulated by a broader single-slit diffraction envelope determined by each slit’s finite width.
This distinction helps interpret data. Changing the separation between two slits changes the fine fringe spacing, while changing each slit’s width changes the broader envelope. If a passage reports one feature changing while the other remains fixed, it may be isolating one geometric parameter.
Rule: X-ray diffraction can report structural spacing
Diffraction is not limited to visible-light slits. When wavelength is comparable to repeating structural spacings, a periodic structure can produce diffraction maxima. A common relation is Bragg’s law:
nλ = 2d sin θ.
Given wavelength, order n, and diffraction angle θ, the relation can be used to infer a repeating spacing d. This is a structural inference from wave interference, not a direct photograph of individual atoms.
Thin-film interference uses the same general idea—waves reflected from different interfaces acquire path and sometimes phase differences. Because phase changes on reflection depend on refractive-index relationships, a problem should specify enough information before asking whether a film appears bright or dark at a particular wavelength.
ACTIVE PRACTICE · WAVE PHYSICS
Infer the Change From Fringe Spacing
Use the original small-angle double-slit model: wavelength 600 nm, screen distance 2.0 m, and slit separation 0.50 mm. The predicted adjacent bright-fringe separation is 2.4 mm. Change one variable at a time or explore combinations under the stated approximation.
Calculated adjacent fringe spacing: mm.
Δy ≈ λL/d assumes the small-angle double-slit regime. The points mark maxima positions, not a calculated diffraction-envelope intensity profile.
Check your reasoning
Choose an answer before opening its feedback.
Check 1
In a double-slit setup, wavelength and screen distance stay fixed while slit separation doubles. What happens to adjacent fringe spacing?
A. It halves.
Correct. Δy is inversely proportional to d.
B. It doubles.
Review this choice. Doubling slit separation makes fringes closer together.
C. It remains unchanged.
Review this choice. Slit separation appears directly in the denominator.
D. It becomes zero for all finite d.
Review this choice. Finite slit separation produces finite fringe spacing.
Check 2
A single slit becomes narrower while wavelength is unchanged. What happens to the diffraction pattern?
A. It broadens.
Correct. Smaller a requires larger angles to satisfy the minima relation.
B. It narrows to zero width.
Review this choice. Narrower apertures increase diffraction.
C. It becomes independent of wavelength.
Review this choice. Wavelength remains in the diffraction relation.
D. The wave stops propagating in all cases.
Review this choice. A narrow slit can still transmit and diffract a wave.
Check 3
A diffraction experiment uses known wavelength and records the angle of a crystal diffraction maximum. Which quantity can Bragg’s law help infer?
A. A repeating structural spacing
Correct. d is the spacing in nλ = 2d sin θ.
B. The organism’s heart rate
Review this choice. Bragg diffraction is a structural wave measurement.
C. The exact electron trajectory inside every atom
Review this choice. The relation yields periodic spacing, not a classical trajectory.
D. The gravitational acceleration without any mechanical data
Review this choice. The diffraction relation does not determine g.
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