MCAT content library / Chemistry & physics / Distillation and volatility
Use relative volatility and the head-temperature record to predict which component enriches first and whether a simple or fractionating column can achieve the needed separation.
About 16 minutes, including a two-component fractionation example and checks.
On this page
- Distillation separates by vapor composition
- Concept: the more volatile component enriches the vapor
- Worked application: simple versus fractional distillation
- Pattern: head temperature is evidence, not a purity certificate
- Rule: azeotropes can limit ordinary distillation
- Check your reasoning
- Continue learning
- Sources
Distillation separates by vapor composition
When a liquid mixture is heated, the vapor above it can have a different composition from the liquid. If one component is more volatile, the vapor is generally enriched in that component relative to the boiling liquid. Condensing the vapor therefore creates a fraction whose composition differs from the original mixture.
Volatility is related to vapor pressure and boiling behavior under the specified conditions. The more volatile component typically has the higher vapor pressure and lower boiling point in a simple comparison.
Concept: the more volatile component enriches the vapor
Simple distillation performs essentially one vaporization–condensation separation step. It works well when one component is nonvolatile or when the volatile components differ enough in boiling behavior that the first vapor is strongly enriched in one component.
Fractional distillation adds a column that permits repeated partial vaporization and condensation. Each equilibrium-like stage can enrich the rising vapor in the more volatile component, improving separation when boiling points are closer.
A longer or more efficient fractionating column can improve resolution, but no real column produces infinite stages or perfect separation automatically.
Worked application: simple versus fractional distillation
An original mixture contains equal moles of liquid A and B. At 1 atm, pure A boils at 70°C and pure B at 90°C. Researchers compare simple distillation with a fractionating column and collect equal-volume fractions.
| Setup / fraction | Head temperature | A in collected fraction |
|---|---|---|
| Simple, early fraction | 77°C | 72% |
| Fractional, fraction 1 | 71°C | 94% |
| Fractional, fraction 2 | 76°C | 76% |
| Fractional, late fraction | 88°C | 12% |
The fractionating column produces a much purer early A-rich fraction than simple distillation. As A is depleted from the boiling flask, the vapor becomes progressively richer in B and the head temperature rises toward B’s boiling region.
The 71°C first fraction is strongly enriched in A but is not pure A: composition measurement still reports 6% B. Temperature alone would not justify calling the fraction 100% pure.
Pattern: head temperature is evidence, not a purity certificate
The thermometer at the distillation head samples the vapor reaching the condenser. A relatively stable temperature near one component’s boiling region can indicate that component dominates the vapor, but temperature is influenced by composition, pressure, thermometer placement, and nonideal mixture behavior.
A purity claim therefore needs stronger evidence, such as a composition assay, refractive index, chromatography, or a suitably narrow boiling range under controlled pressure. A plateau is useful process evidence, not a guarantee of molecular purity.
Rule: azeotropes can limit ordinary distillation
Some nonideal liquid mixtures form an azeotrope whose vapor composition equals its liquid composition at a particular mixture ratio. At that composition, repeated ordinary distillation does not further enrich one component because vaporization no longer changes the composition.
If a passage states that a mixture forms an azeotrope, adding more theoretical plates cannot overcome that equilibrium limit by ordinary distillation alone. A different separation strategy or changed conditions may be needed.
This is another reason not to equate “fractional distillation” with “complete separation.” The achievable purity depends on vapor–liquid equilibrium as well as column performance.
ACTIVE PRACTICE · EVIDENCE TO INFERENCE
Distinguish Vapor Enrichment From a Purity Certificate
Original equal-mole mixture at 1 atm: pure A boils at 70°C, pure B at 90°C. Early simple distillation at 77°C collects 72% A. Fractionating-column fractions: 71°C/94% A; 76°C/76% A; 88°C/12% A.
Examine the evidence boundary
All numeric statements apply to the stipulated original conditions. The activity is teaching practice, not a psychometrically validated assessment.
Check your reasoning
Choose an answer before opening its feedback.
Check 1
Component A has the lower boiling point in a two-liquid mixture. Which component is generally enriched in the earliest vapor under ordinary behavior?
A. A
Correct. The more volatile component is preferentially represented in the vapor.
B. B
Review this choice. B is the less volatile component in the stated comparison.
C. Neither; vapor must always equal liquid composition.
Review this choice. Composition differences are what make ordinary distillation possible.
D. Only the component with the larger molar mass, regardless of volatility
Review this choice. Volatility, not molar mass alone, controls the separation.
Check 2
Why does a fractionating column improve separation of two moderately close-boiling liquids?
A. It provides repeated vaporization–condensation enrichment steps.
Correct. Multiple stages progressively enrich the more volatile component in rising vapor.
B. It changes both compounds into new elements.
Review this choice. Distillation is a physical separation.
C. It makes vapor pressure irrelevant.
Review this choice. Vapor–liquid equilibrium is central to the process.
D. It guarantees 100% pure product in one fraction.
Review this choice. Real separation is limited by equilibrium and column efficiency.
Check 3
A mixture reaches an azeotropic composition. What happens during ordinary distillation at that condition?
A. Vapor and liquid have the same composition, limiting further enrichment.
Correct. The mixture distills without composition change at the azeotrope.
B. All intermolecular forces vanish.
Review this choice. An azeotrope is an equilibrium composition, not absence of interactions.
C. Both components stop having vapor pressure.
Review this choice. The mixture is still volatile.
D. Adding more column stages guarantees complete separation.
Review this choice. More stages do not overcome the azeotropic equilibrium limit.
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