MCAT content library / Chemistry & physics / Atomic spectra and the photoelectric effect
Use line spectra and electron-emission thresholds to distinguish photon energy from photon number and to test quantized-energy models.
About 16 minutes, including a hydrogen transition and photoelectric graph example.
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Spectral lines report energy differences
Atoms do not emit or absorb every photon energy continuously. Bound electrons occupy quantized energy states. When an atom changes from a higher-energy state to a lower-energy state, it can emit a photon whose energy equals the difference between those states. Absorption requires a photon that matches an allowed upward transition.
This is why atomic spectra contain discrete lines. Each line corresponds to a particular energy difference rather than to an arbitrary color chosen by the atom.
Concept: photon energy is set by frequency
Photon energy is
E = hf = hc/λ.
Higher frequency means higher photon energy. Longer wavelength means lower photon energy. Changing the number of photons without changing their frequency changes total delivered energy but not the energy carried by each photon.
Worked application: a hydrogen emission line
An original calculation uses hydrogen energy levels E₁ = −13.6 eV and E₂ = −3.4 eV. An electron drops from n = 2 to n = 1.
The emitted photon energy is:
ΔE = (−3.4 eV) − (−13.6 eV) = 10.2 eV.
Using the supplied approximation hc = 1240 eV·nm:
λ = 1240/10.2 ≈ 122 nm.
The transition therefore produces an ultraviolet photon. The direction matters: the downward transition emits the photon; an upward n = 1 to n = 2 transition would require absorption of a photon with the same energy under the idealized model.
Pattern: photoelectric thresholds separate energy from intensity
In the photoelectric effect, electrons are emitted from a material only when individual photons carry enough energy to overcome the material’s work function φ. For a simple model,
Kmax = hf − φ.
The threshold frequency is therefore
f₀ = φ/h.
If f is below f₀, increasing light intensity does not make each photon energetic enough to eject electrons. If f is above threshold, increasing frequency raises the maximum electron kinetic energy.
| Change | Expected effect above threshold |
|---|---|
| Increase frequency | Kmax increases |
| Increase intensity at same frequency | More photons per time; emission rate can increase |
| Frequency below threshold, intensity increased | No ideal single-photon emission |
For example, if the work function is 2.0 eV and incoming photons carry 3.0 eV each, the maximum emitted-electron kinetic energy is 1.0 eV. Doubling intensity at the same 3.0-eV photon energy does not double Kmax; it increases the photon flux.
Rule: intensity changes photon number, not energy per photon
This distinction links the spectrum and photoelectric examples. Frequency sets photon energy. Intensity describes energy delivered per area per time and can be increased by sending more photons of the same energy.
A brighter beam of subthreshold photons remains subthreshold in the simple one-photon photoelectric model. A dimmer beam of sufficiently high-frequency photons can still eject electrons, though fewer photons per time can mean fewer emission events.
ACTIVE PRACTICE · QUANTIZED LIGHT
Keep Photon Energy Separate From Photon Flux
The original photoelectric model uses Kmax = Ephoton − φ above threshold. In its worked example, the work function is 2.0 eV, each incident photon carries 3.0 eV, and the maximum electron kinetic energy is 1.0 eV. Below threshold, the ideal single-photon model emits no photoelectrons.
Maximum emitted-electron kinetic energy: .
Photon energy exceeds threshold; increasing flux can increase the emission rate under the same quantum efficiency, not Kmax.
Photon flux is an independently set experimental input; emission rate also depends on material quantum efficiency. At exactly threshold, ideal Kmax = 0 eV.
Check your reasoning
Choose an answer before opening its feedback.
Check 1
An electron drops from a higher atomic energy level to a lower one. What happens?
A. A photon can be emitted with energy equal to the level difference.
Correct. The transition energy appears as photon energy in the ideal model.
B. The atom must absorb a photon.
Review this choice. Absorption corresponds to an upward transition.
C. Photon energy is unrelated to the level spacing.
Review this choice. The line energy directly reflects ΔE.
D. The emitted photon has zero frequency.
Review this choice. A nonzero energy difference gives a nonzero photon frequency.
Check 2
Light is below a metal’s photoelectric threshold frequency. Intensity is increased tenfold while frequency is unchanged. What happens in the ideal single-photon model?
A. Electrons still are not emitted.
Correct. Each photon remains below the work-function energy.
B. Electrons are emitted with ten times the kinetic energy.
Review this choice. Intensity does not raise energy per photon.
C. Photon frequency rises automatically.
Review this choice. Frequency was specified as unchanged.
D. The work function becomes zero.
Review this choice. Beam intensity does not redefine the material’s work function.
Check 3
A photon’s wavelength decreases while it remains in vacuum. What happens to its energy?
A. It increases.
Correct. E = hc/λ.
B. It decreases.
Review this choice. Energy is inversely proportional to wavelength.
C. It remains fixed for all wavelengths.
Review this choice. Photon energy depends on frequency and wavelength.
D. It becomes negative.
Review this choice. Photon energy remains positive.
Continue learning
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